MCQ
What is the maximum number of open chain structures possible for ${C_4}{H_8}$
- A$2$
- ✓$4$
- C$3$
- D$1$
✓
Answer
Correct option: B.
$4$
b
(b) Three isomeric structures are possible for ${C_4}{H_8}$
(b) Three isomeric structures are possible for ${C_4}{H_8}$
${H_2}C = CH - C{H_2} - C{H_3}$
$C{H_3} - CH = CH - C{H_3}$ (cis-trans)
$\begin{array}{*{20}{c}}
{C{H_3} - C = C{H_2}} \\
| \\
{\,\,\,\,C{H_3}}
\end{array}$
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