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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
What is the molar solubility of $Al(OH)_3$ in $0.2\, M\, NaOH$ solution? Given that, solubility product of $Al(OH)_3 = 2.4 \times 10^{-24}$ 
  • A
    $3 \times {10^{ - 19}}$
  • B
    $12 \times {10^{ - 21}}$
  • C
    $12 \times {10^{ - 23}}$
  • ✓
    $3 \times {10^{ - 22}}$
✓

Answer

Correct option: D.
$3 \times {10^{ - 22}}$
d
$Al(O{H_3}) \rightleftharpoons \mathop {A{l^{3 + }}}\limits_s  + \mathop {3O{H^ - }}\limits_{(3s + 0.2)} $

$2.4 \times {10^{ - 24}} = s{(3s + 0.2)^3}$

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