MCQ
What is the oxidation number of Si in the compound CaSiO3?
- A−4
- B+2
- C−2
- D+4
Explanation:
CaSiO3
Total charge present = 0.
Oxidation no. of Oxygen is −2.
Oxidation no. od Calcium is +2.
Let, oxidation no. of Slilicon be X.
So, [+2] + x + 3[−2] = 0
2 + x − 6 = 0
x = 4
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CaO(s) + CO2(g) → CaCO3(s);
$\Delta_\text{r}\text{H}^\circ=-178.3\text{kJ mol}^{-1}$