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The amplitude of a particle executing $SHM$ is $3\,cm$. The displacement at which its kinetic energy will be $25 \%$ more than the potential energy is: $.............cm$.
A body executes $SHM$ under the influence of one force and has a period $T_1\, second$ and the same body executes $SHM$ with period $T_2\, second$ when under the influence of another force. When bothforces act simultaneously and in the same direction, then the time period of the same body is
The potential energy of a simple harmonic oscillator of mass $2\, kg$ in its mean position is $5\, J.$ If its total energy is $9\,J$ and its amplitude is $0.01\, m,$ its time period would be
To find the spring constant $(k)$ of a spring experimentally, a student commits $2 \%$ positive error in the measurement of time and $1 \%$ negative error in measurement of mass. The percentage error in determining value of $\mathrm{k}$ is :
A spring has a certain mass suspended from it and its period for vertical oscillation is $T$. The spring is now cut into two equal halves and the same mass is suspended from one of the halves. The period of vertical oscillation is now
A particle doing simple harmonic motion, amplitude $= 4\, cm$, time period $= 12\, sec$. The ratio between time taken by it in going from its mean position to $2 \,cm$ and from $2\, cm$ to extreme position is
A particle performs $SHM$ on $x-$ axis with time period of $0.5\,sec,$ such that it's velocity is zero at $x = -3\,cm$ and at $x = 9\,cm$. It was located at $x = 0$ and moving in negative $'x'$ at $t = 0$. The equation of $SHM$ of the particle is