MCQ
What is the $PH$ of $10^{-9}\, M$ aqueous $HCl$ solution
- A$9$
- ✓between $6$ to $7$
- C$7$
- Dcan't determine
$H C l=10^{-9} \,M=0.01 \times 10^{-7}$
When $HCl$ added to water the total $H ^{\text {+ }}$ ions
$H^{+} =0.01 \times 10^{-7}+10^{-7}$
$H^{+} =1.01 \times 10^{-7}$
$p H =-\log \left(1.01 \times 10^{-7}\right)$
$p H= 6.9$
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