MCQ
What is the potential energy of the electron in the $L-$ shell of the hydrogen atom? .............. $\mathrm{eV}$
- A$-13.6$
- ✓$-6.8$
- C$-10.2$
- D$-3.4$
but Potential energy of electron $=-2\left(E_{n}\right)=-\frac{27.2 \mathrm{eV}}{n^{2}}$ Therefore, for $n=2$
$P.E. =-\frac{27.2 \mathrm{eV}}{4}=-6.8 \mathrm{eV}$
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