Question
What is the probability that an ordinary year has 53 Mondays?
✓
Answer
There are 365 days in an ordinary year,
Total number of outcomes = 365
Since in an ordinary year there are 52 weeks,
There will surely be 52 Mondays.
Now, 52 × 7 = 364 days
So, the last day could be any of the 7 days of the week.
Thus, P(the last day is a Monday)
$=\frac{1}{7}$
Total number of outcomes = 365
Since in an ordinary year there are 52 weeks,
There will surely be 52 Mondays.
Now, 52 × 7 = 364 days
So, the last day could be any of the 7 days of the week.
Thus, P(the last day is a Monday)
$=\frac{1}{7}$
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