Question
What is the relationship between molar mass and electro chemical equivalent. Derive the equation.
✓
Answer
1. Consider the following general electro chemical redox reaction
$
M^{n+}(a q)+n e^{-} \rightarrow M_{(s)}
$
2. We can infer from the above equation that ' $n$ ' moles of electrons are required to precipitate
3. The quantity of charge required to precipitate 1 mole of $M^{n+}=$ Charge of ' $n^{\prime}$ moles of electrons $= nF$
4. In other words, the mass of the substance deposited by one coulomb of charge. Molar mass (M)
Electro chemical equivalent $M ^{ n +}=\frac{\operatorname{Molar} \operatorname{mass}( M )}{ n (96500)}$
(or)
$
Z=\frac{\text { Equivalent mass }}{96500}
$
$
M^{n+}(a q)+n e^{-} \rightarrow M_{(s)}
$
2. We can infer from the above equation that ' $n$ ' moles of electrons are required to precipitate
3. The quantity of charge required to precipitate 1 mole of $M^{n+}=$ Charge of ' $n^{\prime}$ moles of electrons $= nF$
4. In other words, the mass of the substance deposited by one coulomb of charge. Molar mass (M)
Electro chemical equivalent $M ^{ n +}=\frac{\operatorname{Molar} \operatorname{mass}( M )}{ n (96500)}$
(or)
$
Z=\frac{\text { Equivalent mass }}{96500}
$
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