Given that :
$F{e^{2 + }} + 2{e^ - } \to Fe;$ ${E^o}_{F{e^{2 + }}/Fe} = - 0.47\,V$
$F{e^{3 + }} + {e^ - } \to F{e^{2 + }};$ ${E^o}_{F{e^{3 + }}/F{e^{2 + }}} = + 0.77\,V$
- ✓$-0.057$
- B$+0.057$
- C$+0.30$
- D$-0.30$
Given that :
$F{e^{2 + }} + 2{e^ - } \to Fe;$ ${E^o}_{F{e^{2 + }}/Fe} = - 0.47\,V$
$F{e^{3 + }} + {e^ - } \to F{e^{2 + }};$ ${E^o}_{F{e^{3 + }}/F{e^{2 + }}} = + 0.77\,V$
$(i)\,F{e^{2 + }}\, + \,2{e^ - }\, \to \,Fe;$ ${E^o}\, = \, - 0.47\,\,V;$
$(ii)\,F{e^{3 + }}\, + \,{e^ - }\, \to \,F{e^{2 + }};$ ${E^o}\, = \, + 0.77\,\,V;$
$(iii)\,F{e^{3 + }}\, + \,3{e^ - }\, \to Fe$
$(i)\,\Delta {G^o}\, = \, - nF{E^o}\, = \, - \,2\,( - 0.47)F\, = \,0.94\,F$
$(ii)\,\Delta {G^o}\, = \, - nF{E^o}\, = \, - \,1\,( + 0.77)F\, = \, - 0.77\,F$
$(iii)$ on adding $:\,\Delta {G^o}\, = \, + \,0.17\,F$
$\Delta {G^o}\, = \, - nF{E^o}\,{E^o}$ for
$(F{e^{3 + }} \to Fe)\, = \,\frac{{\Delta {G^o}}}{{ - nF}}\,$ $ = \,\frac{{0.17F}}{{ - 3F}}\, = \, - \,0.057\,V$
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$ArN _{2} Cl \overset{Cu / HCl}{\rightarrow} ArCl + N _{2}$ is known as
($en=$ ethylenediamine)
Method $1\,:\,$ $RBr\xrightarrow[diethyl\,\,ether]{Mg}RMgBr\xrightarrow[2.\,{{H}_{3}}{{O}^{+}}]{1.\,C{{O}_{2}}}RC{{O}_{2}}H$
Method $2\,:\,$ $RBr\xrightarrow{NaCN}RCN\xrightarrow[heat]{{{H}_{2}}O,HCl}RC{{O}_{2}}H$
Which one of the following statements correctly describes this conversion ?