Question
What is the temperature which has the same numerical value in kelvin scale and Fahrenheit scale?

Answer

Let x be the required value in Kelvin and Fahrenheit scales.
$\frac{\text{x}-273}{373-273}=\frac{\text{x}-32}{212-32}$
$\frac{\text{x}-273}{100}=\frac{\text{x}-32}{180}$
$9(\text{x}-273)=5(\text{x}-32)$
$\Rightarrow9\text{x}-2457=5\text{x}-160$
$4\text{x}=2457-160=2297$
$\text{x}=\frac{2297}{4}=574.25^\circ$
$574.25\text{K}=574.25^\circ\text{F}.$

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