MCQ
What is the value of $4^2 \times 4^{-2}\ ?$
  • A
    $16$
  • B
    $8$
  • $1$
  • D
    $0$

Answer

Correct option: C.
$1$
C.  $1$
Solution:
$4^2 \times 4^{-2}$
By law of exponents:
$= 4^{2+(-2)} = 4^{2-2} = 4^0 = 1$

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