- Asin x + tan x sec x
- Bcos x + tan x sec x
- Csin x + tan x
- Dsin x + tan x sec2x
Solution:
We follow product rule $\frac{\text{d}}{\text{dx}}(\text{f}.\text{g})=\text{g.}\frac{\text{d}}{\text{dx}}(\text{f})+(\text{f})\frac{\text{d}}{\text{dx}}(\text{f}.\text{g})$
Here, f = sin x and g = tan x
$\frac{\text{d}}{\text{dx}}$ (sin x tan x) = cos x tan x + sec2 x sinx
$\frac{\text{d}}{\text{dx}}$ (sin x tan x) = sin x + tan x sec x
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x and b are real numbers. If b > 0 and |x| > b, then:
$\text{x}\in(-\text{b},\infty)$
$\text{x}\in(\infty,-\text{b})$
$\text{x}\in(-\text{b},\text{b})$
$\text{x}\in(-\infty,-\text{b})\cup(\text{b},\infty)$
If the two lines are perpendicular then difference of their inclination angle is: