Question
What must be the temperature in Fahrenheit so that it will be twice its value in Celsius?
✓
Answer
Data: F = 2 C ∴ C = F/2, F = ?
$\begin{aligned} \frac{F-32}{9} & =\frac{C}{5} \\ \therefore \frac{F-32}{9} & =\frac{F / 2}{5} \\ \therefore F-32 & =\frac{9}{5}\left(\frac{F}{2}\right)=1.8 \frac{F}{2}=0.9 F\end{aligned}$
∴ F – 0.9 F = 32
∴ 0.1 F = 32
∴ F =320.1 = 320 °F.
$\begin{aligned} \frac{F-32}{9} & =\frac{C}{5} \\ \therefore \frac{F-32}{9} & =\frac{F / 2}{5} \\ \therefore F-32 & =\frac{9}{5}\left(\frac{F}{2}\right)=1.8 \frac{F}{2}=0.9 F\end{aligned}$
∴ F – 0.9 F = 32
∴ 0.1 F = 32
∴ F =
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