Gujarat BoardEnglish MediumSTD 7MATHSFractions3 Marks
Question
What should be added to $6\frac{3}{5}$ to get $15$?
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Answer
Required number to be added $=15-6\frac{3}{5}$
$=\frac{15}{6}-\frac{33}{5}$
$=\frac{75-33}{5}$ [$\because$ $LCM$ $1$ and $5$ $= 5$ ] $=\frac{42}{5}=8\frac{2}{5}$
Hence, the required number is $8\frac{2}{5}$
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