Question
What should be added to $6\frac{3}{5}$ to get 15?

Answer

Required number to be added
$=15-6\frac{3}{5}$
$=\frac{15}{6}-\frac{33}{5}$
$=\frac{75-33}{5}$ [$\because$ LCM 1 and 5 = 5 ]
$=\frac{42}{5}=8\frac{2}{5}$
Hence, the required number is $8\frac{2}{5}$

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