Question
What should be added to $6\frac{7}{15}$ to get $8\frac{1}{5}$?
✓
Answer
Let $x$ be added to $6\frac{7}{15}$ to get $8\frac{1}{5}$
Therefore, $6\frac{7}{15}+\text{x}=8\frac{1}{5}$
Thus, we have: $\text{x}=8\frac{1}{5}-6\frac{7}{15}$
$=\frac{41}{5}-\frac{97}{15}$ $L.C.M$. of $5$ and $15 = (5 \times 3) = 15 =\frac{(123-97)}{15}$
$\Big(\frac{15}{5}=3,3\times41=123\Big)$
and $\Big(\frac{15}{15}=1,1\times97=97\Big)$
$=\frac{26}{15}$
$=1\frac{11}{15}$
Therefore, $6\frac{7}{15}+\text{x}=8\frac{1}{5}$
Thus, we have: $\text{x}=8\frac{1}{5}-6\frac{7}{15}$
$=\frac{41}{5}-\frac{97}{15}$ $L.C.M$. of $5$ and $15 = (5 \times 3) = 15 =\frac{(123-97)}{15}$
$\Big(\frac{15}{5}=3,3\times41=123\Big)$
and $\Big(\frac{15}{15}=1,1\times97=97\Big)$
$=\frac{26}{15}$
$=1\frac{11}{15}$
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