Question
What should be added to $\frac{-7}{8}$ so as to get $\frac{5}{9}?$
✓
Answer
Let the required number be x
$\frac{-7}{8}+\text{x}=\frac{5}{9}$
$\text{x}=\frac{5}{9}-\frac{7}{9}$
$\text{x}=\frac{5\times8}{9\times8}-\frac{-7\times9}{8\times9}$
$\text{x}=\frac{40}{72}-\frac{63}{72}$
$\text{x}=\frac{40+63}{72}$
$\text{x}=\frac{103}{72}$
The required number is $\frac{103}{72}$
$\frac{-7}{8}+\text{x}=\frac{5}{9}$
$\text{x}=\frac{5}{9}-\frac{7}{9}$
$\text{x}=\frac{5\times8}{9\times8}-\frac{-7\times9}{8\times9}$
$\text{x}=\frac{40}{72}-\frac{63}{72}$
$\text{x}=\frac{40+63}{72}$
$\text{x}=\frac{103}{72}$
The required number is $\frac{103}{72}$
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