Question
What should be added to $\frac{-7}{8}$ to get $\frac{5}{9}?$
✓
Answer
Let the required number be $x$ $\text{x}+\Big(\frac{-7}{8}\Big)$
$\Rightarrow\text{x}=\frac{5}{9}-\Big(\frac{-7}{8}\Big)$
$=\frac{5}{9}+\frac{-7}{8}$
$LCM$ of $9$ and $8$ is $72$ $=\frac{40+63}{72}$
$\frac{103}{72}$
Hence, the other number is $\frac{103}{72}$
$\Rightarrow\text{x}=\frac{5}{9}-\Big(\frac{-7}{8}\Big)$
$=\frac{5}{9}+\frac{-7}{8}$
$LCM$ of $9$ and $8$ is $72$ $=\frac{40+63}{72}$
$\frac{103}{72}$
Hence, the other number is $\frac{103}{72}$
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