Question
What should be added to $9\frac{2}{3}$ to get $19?$
✓
Answer
Let x be added to $9\frac{2}{3}$ to get $19$
Therefore, $9\frac{2}{3}+\text{x}=19$ Thus,
we have: $\text{x}=19-9\frac{2}{3}$ $=\frac{19}{1}-\frac{29}{3}$
$L.C.M.$ of $1$ and $3$ is 3$=\frac{(57-29)}{3}$
$\Big(\frac{3}{1}=3,3\times19=57\Big)$
and $\Big(\frac{3}{3}=1,1\times29=29\Big)$
$=\frac{28}{3}$
$=9\frac{1}{3}$
Therefore, $9\frac{2}{3}+\text{x}=19$ Thus,
we have: $\text{x}=19-9\frac{2}{3}$ $=\frac{19}{1}-\frac{29}{3}$
$L.C.M.$ of $1$ and $3$ is 3$=\frac{(57-29)}{3}$
$\Big(\frac{3}{1}=3,3\times19=57\Big)$
and $\Big(\frac{3}{3}=1,1\times29=29\Big)$
$=\frac{28}{3}$
$=9\frac{1}{3}$
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