Question
What should be added to $\Big(\frac{-13}{4}+\frac{-3}{8}\Big)$

Answer

$1-\Big(\frac{-13}{4}+\frac{-3}{8}\Big)$
LCM of 4 and 8 = 8
$\therefore1=\frac{1\times8}{1\times8}=\frac{8}{8}$
$\frac{-13}{4}=\frac{-13\times2}{4\times2}=\frac{-26}{8}$
$\therefore1-\Big(\frac{-13}{4}+\frac{-3}{8}\Big)$
$=\frac{8}{8}-\Big(\frac{-26}{8}+\frac{-3}{8}\Big)$
$=\frac{8}{8}+\frac{26}{8}+\frac{3}{8}$
$=\frac{8+26+3}{8}=\frac{37}{8}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free