Question
What values of x will make $DE || AB$ in the given figure?

Answer

$In the figure, in $\triangle\text{ABC},$$
$DE || AB$

$\therefore\frac{\text{AD}}{\text{DC}}=\frac{\text{BE}}{\text{EC}}$
$\Rightarrow\frac{3\text{x}+19}{\text{x}+3}=\frac{3\text{x}+4}{\text{x} }$
$\Rightarrow x(3x + 19) = (x + 3)(3x + 4)$
$\Rightarrow 3x^2 + 19x = 3x^2 + 4x + 9x + 12$
$\Rightarrow 3x^2 + 19x - 3x^2 - 4x - 9x = 12$
$\Rightarrow6\text{x}=12\Rightarrow\text{x}=\frac{12}{6}=2$
$\therefore$ $x = 2$

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