MCQ
What will be de-Broglie wavelength of an electron moving with a velocity of $1.2 \times {10^5}\,m{s^{ - 1}}$
- A$6.068 \times {10^{ - 9}}$
- B$3.133 \times {10^{ - 37}}$
- ✓$6.626 \times {10^{ - 9}}$
- D$6.018 \times {10^{ - 7}}$
$\lambda = \frac{h}{{mv}}$$ = \frac{{6.62 \times {{10}^{ - 34}}}}{{9.1 \times {{10}^{ - 31}} \times 1.2 \times {{10}^5}}}$
$\lambda = 6.626 \times {10^{ - 9}}m$.
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