
- ✓Gatterman Koch reaction
- BEtard reaction
- CGattermann reaction
- DRosenmund reaction

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(I)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow[{5\% \,\,water}]{{95\% \,\,\,acetone}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
$(II)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow[{10\% \,\,water}]{{90\% \,\,\,acetone}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
$(III)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow[{20\% \,\,water}]{{80\% \,\,\,acetone}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
$(IV)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow{{100\% \,water}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
Arrange these reactions in decreasing order of greater proportion of inverted product and select correct answer from the codes given below :
$\begin{array}{*{20}{c}}
{^{C{H_3}}} \\
{_H}
\end{array}\begin{array}{*{20}{c}}
{{\text{ }}\backslash {\text{ }}} \\
/
\end{array}\mathop C\limits^{} {\mkern 1mu} = \mathop C\limits^{} {\mkern 1mu} \begin{array}{*{20}{c}}
/ \\
{{\text{ }}\backslash {\text{ }}}
\end{array}_{\mathop C\limits^{} {\kern 1pt} \equiv \mathop C\limits^{} {\kern 1pt} - \mathop C\limits^{} {\kern 1pt} {H_2}\mathop C\limits^{} {\kern 1pt} {H_3}}^H{\mkern 1mu} $
