MCQ
What will be the $pH$ of a ${10^{ - 8}}\,M\,HCl$ solution
- A$8$
- B$7$
- ✓$6.958$
- D$14.04$
$HCl\, ⇌ \,[{H^ + }]\,\,[C{l^ - }]$
Total $[{H^ + }] = {[{H^ + }]_{{H_2}O}} + {[{H^ + }]_{HCl}}$ $ = {10^{ - 7}} + {10^{ - 8}}$
$ = {10^{ - 7}}[1 + {10^{ - 1}}]$
$[{H^ + }] = {10^{ - 7}} \times \frac{{11}}{{10}}$
$pH=-\log \,[{{H}^{+}}]=-\log \left( {{10}^{-7}}+\frac{11}{10} \right)$ $pH=6.958$
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Statement $(I)$ : Both metal and non-metal exist in $\mathrm{p}$ and $d$-block elements.
Statement $(II)$ : Non-metals have higher ionisation enthalpy and higher electronegativity than the metals.
In the light of the above statements, choose the most appropriate answer from the option given below:
$\left[\right.$ Given : $pK _{ b }\left( NH _3\right)=4.745$
$\log 2=0.301$
$\log 3=0.477$
$T =298\,K ]$