MCQ
What will be the $pH$ value of $0.05 \,M$ $Ba{(OH)_2}$ solution
- A$12$
- ✓$13$
- C$1$
- D$12.96$
$pOH = \log \frac{1}{{{{[OH]}^ - }}} = \log \frac{1}{{.1}} = 1$
$pH + pOH = 14$; $pH + 1 = 14$; $pH = 14 - 1 = 13$
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| Observation | $[A]$ | $[B]$ | Rate of reaction |
| $1$ | $0.1$ | $0.1$ | $2\times10^{-3}\, mol\, L^{-1}\,sec^{-1}$ |
| $2$ | $0.2$ | $0.1$ | $0.4\times10^{-2}\, mol\, L^{-1}\,sec^{-1}$ |
| $3$ | $0.1$ | $0.2$ | $1.4\times10^{-2}\, mol\, L^{-1}\,sec^{-1}$ |
$L(1s^2, 2s^2 2p^4); Q(1s^2, 2s^2 2p^6, 3s^2 3p^5)$
$P(1s^2, 2s^2 2p^6, 3s^1); R(1s^2, 2s^2 2p^6, 3s^2)$
The formulae of ionic compounds that can be formed between these elements are