Question
What will be the time period of oscillation, if the length of a second pendulum is one third?

Answer

$\frac{\text{T}_2^2}{\text{T}_2^1}=\frac{\text{l}_2}{\text{l}_1}=\frac{\text{l}}{\frac{3}{1}}=\frac{1}{3}$$\text{T}^2_2=\frac{(2)^2}{3}$
$\text{T}_2=\frac{2}{\sqrt{3}}\text{ sec}$

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