- A$pH=4.70$
- B$pH < 4.70$
- C$pH$ of solution will be equal to $pH$ of acetic acid
- ✓$4.76 < pH < 5.0$
$ = 4.76 + \log \,\frac{{\frac{{7.5}}{{500}}}}{{\frac{5}{{500}}}} = 4.7 + \log \,1.5 = 4.87$
Hence correct answer is $4.76 < pH < 5.0$
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$\mathrm{HF}, \mathrm{H}_2 \mathrm{O}, \mathrm{SO}_2, \mathrm{H}_2, \mathrm{CO}_2, \mathrm{CH}_4, \mathrm{NH}_3, \mathrm{HCl}, \mathrm{CHCl}_3, \mathrm{BF}_3$
${H_2}O + {H_2}PO^-_4 \rightleftharpoons {H_3}{O^ + } + HPO_4^{ - 2}$
Select out the group of acidic species lying on the right side of the equilibrium
$(II)\,\,\,{{H}_{2}}C=CH-C{{H}_{2}}-\overset{+}{\mathop{C}}\,H-C{{H}_{3}}$
$(III)\,\,\,\begin{matrix}
\,\,\,\,\,C{{H}_{3}}\, \\
|\, \\
{{H}_{3}}C-C-\overset{+}{\mathop{C}}\,{{H}_{2}} \\
|\, \\
\,\,\,C{{H}_{3}} \\
\end{matrix}$