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STD 11 - 8.3. Organic chemistry purification and characterization — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 8.3. Organic chemistry purification and characterization4 Marks
MCQ
When $0.15\, \mathrm{~g}$ of an organic compound was analyzed using Carius method for estimation of bromine, $0.2397 \,\mathrm{~g}$ of $AgBr$ was obtained. The percentage of bromine in the organic compound is $.....$ (Nearest integer)

[Atomic mass : Silver $=108$, Bromine $=80]$

  • A
    $96$
  • B
    $12$
  • C
    $85$
  • ✓
    $68$
✓

Answer

Correct option: D.
$68$
d
Moles of $\mathrm{Br}=$ Moles of $\mathrm{AgBr}$ obtained

$\Rightarrow \quad$ Mass of $\mathrm{Br}=\frac{0.2397}{188} \times 80\, \mathrm{~g}$

therefore $\%$ Br in the organic compound

$=\frac{W_{\text {Br }}}{W_{T}} \times 100$

$=\frac{0.2397 \times 80}{188 \times 0.15} \times 100=0.85 \times 80$

$=68$

$\Rightarrow$ Nearest integer is $'68^{\prime}$

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