a
$1.$ $HCl + NaOH \longrightarrow NaCl + H _2 O$
$n =100 \times 1=100 m \text { mole }=0.1 mole$
Energy evolved due to neutralization of $HCl$ and $NaOH =0.1 \times 57=5.7 kJ =5700$ Joule
Energy used to increase temperature of solution $=200 \times 4.2 \times 5.7=4788$ Joule
Energy used to increase temperature of calorimeter $=5700-4788=912 Joule$
$ms . \Delta t =912$
$m . s \times 5.7=912$
$ms =160 \text { Joule } /{ }^{\circ} C \text { [Calorimeter constant] }$
Energy evolved by neutralization of $CH _5 COOH$ and $NaOH$
$=200 \times 4.2 \times 5.6+160 \times 5.6=5600 \text { Joule }$
So energy used in dissociation of $0.1 mole CH _3 COOH =5700-5600=100$ Joule Enthalpy of dissociation $=1 kJ / mole$
$2.$ $CH _3 COOH =\frac{1 \times 100}{200}=\frac{1}{2}$
$CH _3 CONa =\frac{1 \times 100}{200}=\frac{1}{2}$
$pH = pK _{ a }+\log \frac{[\text { salt }]}{[\text { acid }]}$
$pH =5-\log 2+\log \frac{1 / 2}{1 / 2}$
$pH =4.7$