Question
When $_{15}P^{30}$ decays to become $_{14}Si^{30},$ which particle is released?
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Answer
The nuclear reaction$: _{15}P^{30} \rightarrow _4Si^{30}+ _{+1}e^0$
Thus a positron is emitted during the decay of $_{15}P^{30} $ into $_{14}Si^{30}.$
Thus a positron is emitted during the decay of $_{15}P^{30} $ into $_{14}Si^{30}.$
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