MCQ
When ${ }_{15} \mathrm{P}^{30}$ decays to become ${ }_{14} \mathrm{Si}^{30}$, which particle is released?
- AElectron
- B$\alpha-$particle
- CNeutron
- ✓Positron
✓
Answer
Correct option: D.
Positron
The nuclear reaction: ${ }_{15} \mathrm{P}^{30} \rightarrow{ }_4 \mathrm{Si}^{30}+{ }_{+1} \mathrm{e}^0$
Thus a positron is emitted during the decay of ${ }_{15} \mathrm{P}^{30}$ into ${ }_{14} \mathrm{Si}^{30}$
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