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STD 11 - 9. Hydricarbon — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 9. Hydricarbon4 Marks
MCQ
When 2-bromobutane reacts with alcoholic $KOH$, the reaction is called
  • A
    Halogenation
  • B
    Hydrogenation
  • C
    Chlorination
  • ✓
    Dehydro-halogenation
✓

Answer

Correct option: D.
Dehydro-halogenation
d
(d) $C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,}\limits_{Br\,} }  - C{H_2} - C{H_3}  \xrightarrow{alc.KOH} \mathop {C{H_3}CH = CHC{H_3}}\limits_{{\rm{2 - butene}}} $
The reaction is dehydrohalogenation.

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