Question
When 430J of work was done on a system, it lost 120J of energy as heat. Calculate the value of internal energy change $(\Delta\text{U})$ for this process.

Answer

$\Delta\text{U}=\text{q}+\text{w}$ $\text{q}=-120\text{J}$$\Delta\text{U}=-120+430$ $\text{w}=+430\text{J}$
$\Delta\text{U}=310\text{J}$

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