When a body moves in a circular path, no work is done by the forc… - Vidyadip

MCQ

When a body moves in a circular path, no work is done by the force since

A
there is no net force
B
there is no displacement
C
force is always away from the centre
✓
force and displacement are perpendicular to each other

✓

Answer

Correct option: D.

force and displacement are perpendicular to each other

d
The radial force and displacement are normal to each other in circular motion.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 5.work,energy,power and collision→5.work,energy,power and collision — all question types→Physics STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

Three identical balls are projected with the same speed at angle $30^o, 45^o$ and $60^o$. Their ranges are $R_1 R_2$ and $R_3$ respectively. Then

A wave equation is given as $y = cos\,\,(500t - 70x),$ where $y$ is in $mm$, $x$ in $m$ and $t$ is in $sec$.

A litre of dry air at $STP$ expands adiabatically to a volume of $3$ litres. If $\gamma=1.40,$ the work done by air is$(3^{1.4}=4.6555)$ [Take air to be an ideal gas $]$

In a dilute gas at pressure $P$ and temperature $T$, the mean time between successive collisions of a molecule varies with $T$ as

If the length of a cylinder is $l=(4.00 \pm 0.01) cm$, radius $r =(0.250 \pm 0.001) \;cm$ and mass $m =6.25 \pm 0.01\; g$. Calculate the percentage error in determination of density.

The ratio of the radius of the earth to that of the moon is $10$. The ratio of acceleration due to gravity on the earth and on the moon is $6$. The ratio of the escape velocity from the earth's surface to that from the moon is

A cricket ball of mass $500\, g$ collides with a bat with speed $15\, m/s$ and returns with the same speed within $0.01$ $second$ . The force acted on bat is ............ $ N$

The length of a wire is $1.0\, m$ and the area of cross-section is $1.0 \times {10^{ - 2}}\,c{m^2}$. If the work done for increase in length by $0.2\, cm$ is $0.4\, joule$, then Young's modulus of the material of the wire is

If $\vec{\text{a}}_1$ and $\vec{\text{a}}_2$ are two non collinear unit vectors and $|\vec{\text{a}}_1+\vec{\text{a}}_2|=\sqrt{3},$ then the value of $(\vec{\text{a}}_1-\vec{\text{a}}_2).(2\vec{\text{a}}_1+\vec{\text{a}}_2)$ is:

As the temperature is increased, the time period of a pendulum:

Increases as its effective length increases even though its centre of mass still remains at the centre of the bob.
Decreases as its effective length increases even though its centre of mass still remains at the centre of the bob.
Increases as its effective length increases due to shifting of centre of mass below the centre of the bob.
Decreases as its effective length remains same but the centre of mass shifts above the centre of the bob.