MCQ
When a bulb is powered by a 4 A current, the temperature difference between the filament and the surrounding air is $20^{\circ} C$. What current would result in a temperature difference of $100^{\circ} C$ ?
  • A
    2 A
  • B
    4 A
  • C
    4.5 A
  • 4.67 A

Answer

Correct option: D.
4.67 A
(d)
4.67 A
Explanation:
We know temperature difference $\Delta T \propto I ^2$, when filament, surrounding temperature are fixed.
Now, $20^{\circ} C =273+20=293 K ; 100^{\circ} C =273+100=373 K$.
So, we can write, $\frac{293}{373}=\frac{4^2}{\left(1_2\right)^2}$
or $I _2=4.67 A$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free