MCQ
When a copper ball is heated, the largest percentage increase will occur in its
- ADiameter
- BArea
- ✓Volume
- DDensity
As Volume $\propto(radius)^3$ and Area $\propto ((radius)^2$, so percentage increase will be largest in it’s volume.
Density will decrease with rise in temperature.
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Step $1$ It is first compressed adiabatically from volume $8.0 \,m ^{3}$ to $1.0 \,m ^{3}$.
Step $2$ Then expanded isothermally at temperature $T_{1}$ to volume $10.0 \,m ^{3}$.
Step $3$ Then expanded adiabatically to volume $80.0 \,m ^{3}$.
Step $4$ Then compressed isothermally at temperature $T_{2}$ to volume $8.0 \,m ^{3}$.
Then, $T_{1} / T_{2}$ is

[Take latent heat of fusion for ice as $\frac{{10}}{3} ×10^5 J.kg^{-1} $]