When a load $W$ is hung from a wire of length $2\ L$ , it just breaks. Now this wire is completely melted and a new wire of length $L$ is formed. If the load $W$ is hung from this new wire
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If length halved, area is doubled
$\Rightarrow$ Breaking stress $=\frac{\mathrm{W}}{\mathrm{A}}=\frac{\mathrm{W}^{\prime}}{2 \mathrm{A}}$
to break new wire load $W^{\prime}=2 W$
on applying $W,$ new wire will not break.
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