When a wave travels in a medium, the particle displacement is given by $y\,(x,t) = 0.03\sin \pi (2t - 0.01x)$ where $y$ and $x$ are meters and $t$ in seconds. The phase difference, at a given instant of time between two particle $25 m$. apart in the medium, is
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(b) $y(x,\;t) = 0.03\sin \pi (2t - 0.01x)$ $ = 0.03\sin (2\pi t - 0.01\pi x)$
$k = 0.01\pi = \frac{{2\pi }}{\lambda }$==> $\Delta \phi = \frac{{2\pi }}{\lambda }\Delta x = 0.01\pi \times 25$$ = \frac{\pi }{4}$
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