When acidified $\ce{K_2Cr_2O_7}$ solution is added to $Sn^{2+} $salts then $Sn^{2+}$ changes to
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Thus, Acidified potassium dichromate will oxidize tin $(II)$ to tin $(IV)$
$\text{Cr}_2\text{O}_7^{2-}+14\text{H}^++3\text{Sn}^{2+}\rightarrow2\text{Cr}^{3+}+3\text{Sn}^{4+}+7\text{H}_2\text{O}$
$\text{Cr}_2\text{O}_7^{2-}+14\text{H}^++3\text{Sn}^{2+}\rightarrow2\text{Cr}^{3+}+3\text{Sn}^{4+}+7\text{H}_2\text{O}$
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