MCQ
When alcohol reacts with concentrated ${H_2}S{O_4}$ intermediate compound formed is
- ✓Carbonium ion
- BAlkoxy ion
- CAlkyl hydrogen sulphate
- DNone of these
✓
Answer
Correct option: A.
Carbonium ion
a
(a) In all cases intermediate is carbonium ion, and there may be $1, 2-$ hydride or $1, 2-$ methyl shift to form more stable carbonium ion.
(a) In all cases intermediate is carbonium ion, and there may be $1, 2-$ hydride or $1, 2-$ methyl shift to form more stable carbonium ion.
$ - \mathop C\limits_{\mathop |\limits_H }^| \,\,\,\,\, - \mathop C\limits_{\mathop |\limits_{\,\,\,\,OH} }^| - \overset {{H^ + }} \longleftrightarrow - \mathop C\limits_{\mathop |\limits_{\mathop H\limits_{{\text{Protonated}}\,\,\,{\text{alcohol}}} } }^| - \mathop C\limits_{\mathop |\limits_{{}^ + O{H_2}} }^| - \overset {{H_2}O} \longleftrightarrow $
${\mathop { - \mathop C\limits_{\mathop |\limits_H }^| - \mathop C\limits_|^| - }\limits_{Carbonium\,\,ion} } \overset { - {H^ + }} \longleftrightarrow - \mathop C\limits^| = \mathop C\limits^| - $
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C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}} \\
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