MCQ
When alcohol reacts with concentrated ${H_2}S{O_4}$ intermediate compound formed is
  • Carbonium ion
  • B
    Alkoxy ion
  • C
    Alkyl hydrogen sulphate
  • D
    None of these

Answer

Correct option: A.
Carbonium ion
a
(a) In all cases intermediate is carbonium ion, and there may be $1, 2-$ hydride or $1, 2-$ methyl shift to form more stable carbonium ion.

$ - \mathop C\limits_{\mathop |\limits_H }^| \,\,\,\,\, - \mathop C\limits_{\mathop |\limits_{\,\,\,\,OH} }^|  - \overset {{H^ + }} \longleftrightarrow  - \mathop C\limits_{\mathop |\limits_{\mathop H\limits_{{\text{Protonated}}\,\,\,{\text{alcohol}}} } }^|  - \mathop C\limits_{\mathop |\limits_{{}^ + O{H_2}} }^|  - \overset {{H_2}O} \longleftrightarrow $

${\mathop { - \mathop C\limits_{\mathop |\limits_H }^|  - \mathop C\limits_|^|  - }\limits_{Carbonium\,\,ion} } \overset { - {H^ + }} \longleftrightarrow  - \mathop C\limits^|  = \mathop C\limits^|  - $

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