MCQ
When benzoic acid is treated with $PC{l_5}$ at $100\,^o C$, it gives
- ✓Benzoyl chloride
- B$o-$ chlorobenzoic acid
- C$p-$ chlorobenzoic acid
- DBenzyl chloride
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(1)${H_2} \to {H^ \bullet } + {H^ \bullet }$
(2)$B{r_2} \to B{r^ \bullet } + B{r^ \bullet }$
(3)$B{r^ \bullet } + HBr \to {H^ \bullet } + B{r_2}$
(4)${H^ \bullet } + B{r_2} \to HBr + B{r^ \bullet }$
(5)$B{r^ \bullet } + B{r^ \bullet } \to B{r_2}$
When $P$ is going to form $PF_5$, then these radial distances are going to become arbitrarily ____,____and ____ respectively
