b (b)In parallel, equivalent resistance is low $\left( {i = \frac{E}{{R + \frac{r}{n}}}} \right)$
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The supply voltage to room is $120\ V$. The resistance of the lead wires is $6\,\Omega$ . A $60\ W$ bulb is already switched on. What is the decrease of voltage across the bulb, when a $240\ W$ heater is switched on in parallel to the bulb? ............. $V$
Two batteries $V_1$ and $V_2$ are connected to three resistors as shown below. If $V_1=2 \,V$ and $V_2=0 \,V$, then the current $I=3 \,mA$. If $V_1=0 \,V$ and $V_2=4 \,V$, then the current $I=4 \,mA$. Now, if $V_1=10 \,V$ and $V_2=10 \,V$, then the current $I$ will be ............ $\,mA$
$E$ denotes electric field in a uniform conductor, $I$ corresponding current through it, ${v_d}$ drift velocity of electrons and $P$ denotes thermal power produced in the conductor, then which of the following graph is incorrect
Suppose the drift velocity $v_d$ in a material varied with the applied electric field $E$ as ${v_d}\, \propto \,\sqrt E $ .Then $V - I$ graph for a wire made of such a material is best given by
A potentiometer has uniform potential gradient. The specific resistance of the material of the potentiometer wire is $10^{-7} \, ohm-meter$ and the current passing through it is $0.1\, ampere$; cross-section of the wire is $10^{-6}\, m^2$. The potential gradient along the potentiometer wire is
In the circuit as shown in the figure, the heat produced by $6\, ohm$ resistance due to current flowing in it is $60$ calorie per second. The heat generated across $3\, ohm$ resistance per second will be ................. $calorie$
Following figures show different combinations of identical bulb$(s)$ connected to identical battery$(ies)$. Which option is correct regarding the total power dissipated in the circuit?
A battery of internal resistance $4$ $\Omega$ is connected to the network of resistances as shown. In order to give the maximum power to the network, the value of $R$ (in $\Omega $) should be
A $100\, W$ bulb $B_1$, and two $60\,W$ bulbs $B_2$ and $B_3$, are connected to a $250\, V$ source, as shown in the figure. Now $ W_1, W_2$ and $W_3$ are the output powers of the bulbs $B_1, B_2$ and $B_3$, respectively. Then