MCQ
When chloroform is treated with excess oxygen it forms
- A$COC{l_2} + HCl$
- B$COC{l_2} + C{l_2} + {H_2}$
- ✓$COC{l_2} + C{l_2} + {H_2}O$
- DNo product will be formed
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${C_{10}}{H_{22}} \xrightarrow{900\,K} {C_4}{H_8} + {C_6}{H_{14}}$
$C$ will be