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STD 11 - 7. Redox reactions — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 7. Redox reactions4 Marks
MCQ
When $Cl_2$ gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from
  • A
    zero to $+1$ and zero to ${-5}$
  • ✓
    zero to ${-1}$ and zero to $+5$
  • C
    zero to ${-1}$ and zero to $+3$
  • D
    zero to $+1$ and zero to $-3$
✓

Answer

Correct option: B.
zero to ${-1}$ and zero to $+5$
b
The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is

$3 \mathrm{Cl}_{2}+6 \mathrm{NaOH} \rightarrow \quad \mathrm{NaClO}_{3}+5 \mathrm{NaCl}+3 \mathrm{H}_{2} \mathrm{O}$

Oxidation number of $\mathrm{Cl}$ is 0 in $\mathrm{Cl}_{2},-1$ in $\mathrm{NaCl}$ and $+5$ in $\mathrm{NaClO}_{3}$

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