MCQ
When $D-$ glucose is treated with $Br_2$ water then the product is :
- ✓

- B

- C

- D






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[Given : ${E^0}_{Zn/Z{n^{ + 2}}} = 0.76\,V,$
${E^0}_{Cu/C{u^{ + 2}}} = - 0.34\,V,\,\frac{{2.303\,RT}}{F} = 0.06,\log 2 = 0.30]$
Select the incorrect option is
${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{ - 4}}\xrightarrow{{MnO_4^ - /{H^ + }}}F{e^{ + 3}} + C{O_2} + NO_3^ - $