MCQ
When ethyl bromide reacts with sodium acetylide the main product is
  • A
    $1-$ butane
  • B
    $1-$ butene
  • $1-$ butyne
  • D
    $2-$ butene

Answer

Correct option: C.
$1-$ butyne
c
(c) Thus in this reaction $1-$ butyne is main product.

$\underset{\text{Ethyl bromide}}{\mathop{{{C}_{2}}{{H}_{5}}Br}}\,+\underset{\text{ sodium}}{\mathop{NaC}}\,\equiv \underset{\text{acetylide}}{\mathop{CH}}\,\to $ $\underset{\text{ }1\text{ -butyne}}{\mathop{{{C}_{2}}{{H}_{5}}C\equiv CH}}\,+\underset{\begin{smallmatrix} 
 \text{sodium } \\ 
 \text{bromide} 
\end{smallmatrix}}{\mathop{NaBr\text{ }}}\,$

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