MCQ
When ethyl bromide reacts with sodium acetylide the main product is
- A$1-$ butane
- B$1-$ butene
- ✓$1-$ butyne
- D$2-$ butene
$\underset{\text{Ethyl bromide}}{\mathop{{{C}_{2}}{{H}_{5}}Br}}\,+\underset{\text{ sodium}}{\mathop{NaC}}\,\equiv \underset{\text{acetylide}}{\mathop{CH}}\,\to $ $\underset{\text{ }1\text{ -butyne}}{\mathop{{{C}_{2}}{{H}_{5}}C\equiv CH}}\,+\underset{\begin{smallmatrix}
\text{sodium } \\
\text{bromide}
\end{smallmatrix}}{\mathop{NaBr\text{ }}}\,$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
The unknown compounds $A$ and $B$ in the above reaction are :
$Cu^{2+}_{(aq)} + e^-\to Cu^+_{(aq)}$ and
$Cu^+_{(aq)} + e^-\to Cu_{(s)}$
are $+0.15\,V$ and $+0.50\,V$ respectively. The value of $E^o_{Cu^{2+}/Cu}$ will be ............ $\mathrm{V}$
