MCQ
When ethyl chloride and alcoholic $ KOH$ are heated, the compound obtained is
- ✓${C_2}{H_4}$
- B${C_2}{H_2}$
- C${C_6}{H_6}$
- D${C_2}{H_6}$
$C{{H}_{3}}C{{H}_{2}}Cl+KOH\to C{{H}_{2}}=C{{H}_{2}}+KCl+{{H}_{2}}O$
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$\begin{array}{*{20}{c}}
{{C_6}{H_5} - C - H} \\
{\,\,\,\,\,\,\,\,\,\,||} \\
{\,\,\,\,\,\,\,\,\,\,\,\,O}
\end{array}\xrightarrow{{N{H_2}OH/{H^ \oplus }}}[X]$
$[X] $ will be :

