MCQ
When glycerol is heated with $KHS{O_4}$ it gives
- A$C{H_2} = CH - C{H_3}$
- B$C{H_2} = CH - C{H_2}OH$
- ✓$C{H_2} = CH - CHO$
- D$C{H_2} = C = C{H_2}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
${{\text{[Fe(F)(Cl)(Br)(I)(N}}{{\text{H}}_3}{\text{)(}}{{\text{H}}_2}{\text{O)]}}^\Theta }$

Given : $\log 2=0.3010$
$\log 3=0.4771$
$\log 5=0.6989$
$\begin{array}{*{20}{c}}
\,\,\,{{C_2}{H_5}} \\
{|\,\,\,\,\,\,\,} \\
{C{H_3} - C - COOH} \\
{|\,\,\,\,\,\,} \\
\,\,\,{{C_3}{H_7}}
\end{array}\xrightarrow{{{N_3}H/Conc.\,{H_2}S{O_4}}}\begin{array}{*{20}{c}}
\,\,\,\,\,\,\,\,\,{{C_2}{H_5}} \\
| \\
{C{H_3} - C - N{H_2}} \\
| \\
\,\,\,\,\,\,\,\,\,{{C_3}{H_7}}
\end{array}$
is called :